type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name.CHAPTER 42. ESSENTIALS 548 julia> function test_let_x() x = 0 map(1:3) do _ x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name.CHAPTER 42. ESSENTIALS 548 julia> function test_let_x() x = 0 map(1:3) do _ x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name.CHAPTER 42. ESSENTIALS 548 julia> function test_let_x() x = 0 map(1:3) do _ x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x

type, the REPL help will tell you: just type ? and then paste the symbol.) Julia will even let you shadow existing exported constants and functions with local ones (although this is not recommended to avoid of it. If you assign to an exist- ing local, it always updates that existing local: you can only shadow a local by explicitly declaring a new local in a nested scope with the local keyword. In particular with three distinct variables being captured (one at each iteration) even though we chose to use (shadow) the same name. julia> function test_let_x() x = 0 map(1:3) do _ x += 1 let x = x return ()->x