notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 11.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 13.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 11.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 11.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 13.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 13.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 14.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 14.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 19.1 Standalone diagram You can also use @startmath/@endmath

notation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath> P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 18.1 Standalone diagram You can also use @startmath/@endmath