PlantUML 1.2019.3 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 11.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 159 页 | 1.76 MB | 1 年前3- PlantUML 1.2019.2 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 11.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 159 页 | 1.76 MB | 1 年前3 - PlantUML 1.2019.1 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 11.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 147 页 | 1.89 MB | 1 年前3 - PlantUML 1.2019.6 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 13.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 173 页 | 1.95 MB | 1 年前3 - PlantUML 1.2019.9 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 13.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 173 页 | 1.97 MB | 1 年前3 - PlantUML 1.2019.4 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 13.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 167 页 | 1.87 MB | 1 年前3 - PlantUML 1.2020.23 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 14.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 306 页 | 3.12 MB | 1 年前3 - PlantUML 1.2020.22 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 14.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 294 页 | 3.03 MB | 1 年前3 - PlantUML 1.2021.2 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 19.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 388 页 | 4.18 MB | 1 年前3 - PlantUML 1.2021.1 Справочное руководство по языкуnotation within PlantUML: @startuml :<math>int_0^1f(x)dxmath>; :<math>x^2+y_1+z_12^34math>; note right Try also <math>d/dxf(x)=lim_(h->0)(f(x+h)-f(x))/hmath>
P(y|\mathbf{x}) \mbox{ or } f note @enduml or: @startuml Bob -> Alice : Can you solve: <math>ax^2+bx+c=0math> Alice --> Bob: <math>x = (-b+-sqrt(b^2-4ac))/(2a)math> @enduml 18.1 Standalone diagram You can also use @startmath/@endmath 0 码力 | 383 页 | 4.13 MB | 1 年前3
共 12 条
- 1
- 2