Composing Ancient Mathematical Knowledge Into Powerful Bit-fiddling| 1111 | a | a 111 | 3a | 2a 11 | 7a | 4a 1 | 15a | 8a=/ seven additions! int mul15_naieve(int a) { int res = 0; int square = a; res0 码力 | 73 页 | 947.99 KB | 5 月前3- 菟葵 - Krita 问题答疑速查 - 2023-02-15A0 码力 | 31 页 | 1.55 MB | 1 年前3
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