Celery v4.4.5 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1215 页 | 1.44 MB | 1 年前3Celery 4.4.0 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1185 页 | 1.42 MB | 1 年前3Celery 4.4.3 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1209 页 | 1.44 MB | 1 年前3Celery 4.4.1 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1188 页 | 1.42 MB | 1 年前3Celery 4.4.2 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1188 页 | 1.42 MB | 1 年前3Celery v4.4.4 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1215 页 | 1.44 MB | 1 年前3Celery v4.4.6 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1216 页 | 1.44 MB | 1 年前3Celery v4.4.7 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 1219 页 | 1.44 MB | 1 年前3Celery 4.4.2 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 797 页 | 2.85 MB | 1 年前3Celery 4.4.1 Documentation
Celery isn’t able to detect what module the function belongs to, it uses the main module name to generate the beginning of the task name. This is only a problem in a limited set of use cases: 1. If the Names Every task must have a unique name. If no explicit name is provided the task decorator will generate one for you, and this name will be based on 1) the module the task is defined in, and 2) the name = hello.apply_async(args=(a, b)) print(r.get(on_message=on_raw_message, propagate=False)) Will generate output like this: {'task_id': '5660d3a3-92b8-40df-8ccc-33a5d1d680d7', 'result': {'progress': 50}0 码力 | 797 页 | 2.85 MB | 1 年前3
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